MATH SOLVE

4 months ago

Q:
# Solve triangle PQR is PQ 9, PR 7, and QR 8. POR is NOT a right triangle.

Accepted Solution

A:

Given => PQ = 9 unit

PR = 7 unit

QR = 8 unit

To find => Area of triangle PQR

We can find area of triangle by Heron's Formula.

Where,

s = (9+7+8)/3

= 24/3

= 8

and,

a = 9

b = 7

c = 8

Heron's Formula = [tex] \sqrt{s(s - a)(s - b)(s - c)} [/tex]

= [tex] \sqrt{8(8 - 9)(8 - 7)(8 - 8)} [/tex]

= [tex] \sqrt{8( - 1)(1)} [/tex]

= [tex] \sqrt{ - 8} [/tex]

= [tex]2i \sqrt{2} [/tex]

Area of triangle = 2iβ2 units

Hope this helps!

PR = 7 unit

QR = 8 unit

To find => Area of triangle PQR

We can find area of triangle by Heron's Formula.

Where,

s = (9+7+8)/3

= 24/3

= 8

and,

a = 9

b = 7

c = 8

Heron's Formula = [tex] \sqrt{s(s - a)(s - b)(s - c)} [/tex]

= [tex] \sqrt{8(8 - 9)(8 - 7)(8 - 8)} [/tex]

= [tex] \sqrt{8( - 1)(1)} [/tex]

= [tex] \sqrt{ - 8} [/tex]

= [tex]2i \sqrt{2} [/tex]

Area of triangle = 2iβ2 units

Hope this helps!