What I the equation in standard form of the line that passes through the points(4,-8) and has a slope of 1/4

Answer:Standard form of the line with point (4,-8) and slope of 1/4  is -x + 4 y = -36.Step-by-step explanation:The slope of the line equation = 1/4The point is given as (4,-8).Now, by POINT SLOPE formula,The line equation  with slope m  nad point (x0,y0) is given as:(y - y0)  = m (x -x0)So, the line equation here is given as [tex]y -(-8)  =  \frac{1}{4} (x -4)\\\implies 4(y + 8)  = x - 4\\4 y + 32 = x - 4\\4y = x - 36[/tex]Now, the standard form of line equation is Ax + By  = CHere,  4y = x - 36   ⇒  4y - x = -36or, -x + 4y = -36 is the standard form.Hence,standard form of the line with point (4,-8) and slope of 1/4 is -x + 4y = -36.