Solutions of aluminum nitrate and sodium sulfate react to form sodium nitrate and aluminum sulfate. Balance this reaction. _Al(NO3)3(aq)+__Na2SO4(aq) —> Al2(SO4)3(s) + ___ NaNO3(aq)1,3,1,62,3,1,62,3,1,33,3,2,6

Answer:2Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → 1Al₂(SO₄)₃(s) + 6NaNO₃(aq)2, 3, 1, 6Second choice.Step-by-step explanation:Count the number of atoms on each side. Keep polyatomic ions together because they exist on both sides. After each coefficient you write in, recount the number of atoms.Al(NO₃)₃(aq) + Na₂SO₄(aq) → Al₂(SO₄)₃(s) + NaNO₃(aq)Al         1                                  Al         2NO₃     3                                 NO₃      1Na        2                                 Na        1SO₄      1                                 SO₄      3Balance the sulfates (SO₄) by multiplying it by 3 on the left. Sodium (Na) will also change.Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + NaNO₃(aq)Al         1                                  Al         2NO₃     3                                 NO₃      1Na        6                                 Na        1SO₄      3                                 SO₄      3Balance sodium (Na) by multiplying it on the left by 6. Nitrate (NO₃) will also change.Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)Al         1                                  Al         2NO₃     3                                 NO₃      6Na        6                                 Na        6SO₄      3                                 SO₄      3Balance the number of nitrates (NO₃) on the left. Multiply by 2. Aluminum (Al) also changes.2Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)Al         2                                  Al         2NO₃     6                                 NO₃      6Na        6                                 Na        6SO₄      3                                 SO₄      3The same number of each atom is on each side, so the equation is balanced.If there is no coefficient, treat it as 1.2,3,1,6