1.The slope of a line is -4, and the y-intercept is -3. What is the equation of the line written in slope-intercept form?y = -4x - 3y = -4x + 3y = 4x - 32.The graph of a line passes through the two points (-2, 1) and (2, 1). What is the equation of the line written in general form?y - 1 = 0x - y + 1 = 0x + y - 1= 03.The slope of a line is -1/3, and the y-intercept is 10/3. What is the equation of the line written in general form?10x + 3y - 1 = 0x + 3y + 10 = 0x + 3y - 10 = 04.Write the equation of the line that has an x-intercept of -3 and passes through the point (-3, 7).x = -3y = -3y = 7
Accepted Solution
A:
In y = mx + b form, the slope is in the m position and the y int is in the b position
1. slope of -4....y int of -3 y = -4x - 3 <==
2. (-2,1)(2,1)...u have the same y coordinates..this means u have a horizontal line with a slope of 0. y = 1......y - 1 = 0 <===
3. slope = -1/3 and y int = 10/3... y = -1/3x + 10/3....add 1/3 to both sides 1/3x + y = 10/3...multiply everything by 3 x + 3y = 10 x + 3y - 10 = 0 <==
4. (-3,7)...and if the x int is -3, then its points are (-3,y)...meaning u have points where the x coordinates are the same...meaning vertical lines...ur answer is x = -3